Answer:
Smaller x value = -1 and y = -2.
Larger x value = 1 and y = 2.
Step-by-Step explanation:
x^2 + y^2 = 5
y = 2x
Substitute y = 2x into the first equation:
x^2 + (2x)^2 = 5
x^2 + 4x^2 = 5
5x^2 = 5
x^2 = 1
x = ±1
So y = 2 * ±1 = ±2
Answer:
(- 1, - 2 ) and (1, 2 )
Step-by-step explanation:
Given the 2 equations
x² + y² = 5 → (1)
y = 2x → (2)
Substitute y = 2x into (1)
x² + (2x)² = 5
x² + 4x² = 5
5x² = 5 ( divide both sides by 5 )
x² = 1 ( take the square root of both sides )
x = ± [tex]\sqrt{1}[/tex] = ± 1
Substitute these values into (2) for corresponding values of y
x = - 1 : y = 2(- 1) = - 2 ⇒ (- 1, - 2 )
x = 1 : y = 2(1) = 2 ⇒ (1, 2 )
The solution with smaller x- value is (- 1, - 2 )
The solution with the larger x value is (1, 2 )