Answer:
The distance between (5, -8) and (5,2) is: d = 10 units
Step-by-step explanation:
Note: I will solve the first question as the procedure solution for the remaining questions is exactly the same.
Given the points
Determining the distance between (5, -8) and (5,2)
[tex]d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}[/tex]
substitute (x₁, y₁) = (2, 3) and (x₂, y₂) = (2, -5)
[tex]=\sqrt{\left(5-5\right)^2+\left(2-\left(-8\right)\right)^2}[/tex]
[tex]=\sqrt{\left(5-5\right)^2+\left(2+8\right)^2}[/tex]
[tex]=\sqrt{0+10^2}[/tex]
[tex]=\sqrt{10^2}[/tex]
[tex]=10[/tex] units
Therefore, the distance between (5, -8) and (5,2) is: d = 10 units
