Answer :
Answer:
f(x) = Ca^x
x = years since 2000.
f(0) = 220000 = Ca^0 = C
f(x) = 220000a^x
f(1) = 220000(1-0.11) = 220000a^1
a = 0.89
f(x) = 220000(0.89)^x
So each year reduces by 89%
Answer:
f(x) = Ca^x
x = years since 2000.
f(0) = 220000 = Ca^0 = C
f(x) = 220000a^x
f(1) = 220000(1-0.11) = 220000a^1
a = 0.89
f(x) = 220000(0.89)^x
So each year reduces by 89%