What is equation of the line graphed below?

[tex](0,0) \longrightarrow \sf{part \: \: of \: \: the \: \: graph} \\ (1, - 3)\longrightarrow \sf{given \: \:coordinate \: \: point}[/tex]
[tex]m = \frac{dy}{dx} = \frac{y_2-y_1}{x_2-x_1}[/tex]
Substitute these coordinate values in.
[tex]m = \frac{0 - ( - 3)}{0 - 1} \\ m = \frac{3}{ - 1} \\ m = - 3[/tex]
Hence, the slope is -3.
From the graph, the line passes through the origin point. Therefore, the y-intercept is (0,0).
[tex]y = mx + b \\ \begin{cases} \sf{m = slope} \\ \sf{b = y - intercept} \end{cases}[/tex]
Substitute both m and b in the slope-intercept form.
[tex]y = - 3x + 0 \\ y = - 3x[/tex]
Hence the answer is y = -3x.
[tex] \large \boxed{y = - 3x}[/tex]