Answer:
C. {-9,-3}
Step-by-step explanation:
[tex]|k+6|=3[/tex] gives [tex]k+6=3[/tex] if [tex]k + 6 \geq 0[/tex]. This gives [tex]k=-3[/tex], which is valid.
It can also give [tex]-(k+6) = 3[/tex] if [tex]k + 6 < 0[/tex]. This gives [tex]k=-9[/tex], which is valid.
Hence the solutions are [tex]k=-9 \vee k=-3[/tex].
