Answer :
Answer:
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m.
We can consider 8 am = 0, and 8:30 am = 30, so [tex]a = 0, b = 30[/tex]
Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Between 15 and 25, so:
[tex]P(15 \leq X \leq 25) = \frac{25 - 15}{30 - 0} = 0.3333[/tex]
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.