Answer:
[tex]f(t) = 1 - cos^2\ t[/tex] and [tex]f(t) = sin^2\ t[/tex]
Step-by-step explanation:
Given
[tex]\frac{sec\ t - cos\ t}{sec\ t} = f(t)[/tex]
Required
Simplify
[tex]f(t) = \frac{sec\ t - cos\ t}{sec\ t}[/tex]
Split fraction
[tex]f(t) = \frac{sec\ t }{sec\ t} - \frac{cos\ t}{sec\ t}[/tex]
[tex]f(t) = 1 - \frac{cos\ t}{sec\ t}[/tex]
[tex]sec\ t = \frac{1}{cos\ t}[/tex]
So, we have:
[tex]f(t) = 1 - \frac{cos\ t}{\frac{1}{cos\ t}}[/tex]
[tex]f(t) = 1 - cos\ t * cos\ t[/tex]
[tex]f(t) = 1 - cos^2\ t[/tex]
In trigonometry:
[tex]1 - cos^2\ t = sin^2\ t[/tex]
So, we have:
[tex]f(t) = sin^2\ t[/tex]
