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Answered

Consider the reaction and the rate law below.

2O3 → 302
R= k[03]2

What is the overall order of the reactants in this rate law?

A. 0
B. 1
C. 2
D. 3​

Consider The Reaction And The Rate Law Below 2O3 302 R K032What Is The Overall Order Of The Reactants In This Rate Law A 0 B 1C 2D 3 class=

Answer :

ARDNI313GO

The overall order of the reactants in this rate law : 2

Further explanation

Given

Reaction

2O3 → 302

The rate law :

R= k[03]²

Required

The overall order

Solution

The overall order  : the sum of orders for each reactant

For A + B ---> C + D

r = k [A]ᵃ[B]ᵇ

The overall reaction order is m+n

So for the rate law of R= k[03]², the overall order = 2

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