Answer:
[tex]h = 162.0\ cm[/tex]
Step-by-step explanation:
Given
[tex]BSA = \frac{\sqrt{w*h}}{60}[/tex]
Required
Find h, when BSA = 1.5 and w = 50
We have:
[tex]BSA = \frac{\sqrt{w*h}}{60}[/tex]
Substitute 1.5 for BSA and 50 for w
[tex]1.5 = \frac{\sqrt{50*h}}{60}[/tex]
Multiply both sides by 60
[tex]60*1.5 = \frac{\sqrt{50*h}}{60}*60[/tex]
[tex]60*1.5 = \sqrt{50*h[/tex]
[tex]90 = \sqrt{50*h[/tex]
Square both sides
[tex]90^2 = (\sqrt{50*h})^2[/tex]
[tex]90^2 = 50*h[/tex]
[tex]90^2 = 50h[/tex]
[tex]8100 = 50h[/tex]
Divide both sides by 50
[tex]\frac{8100}{50} = \frac{50h}{50}[/tex]
[tex]\frac{8100}{50} = h[/tex]
[tex]162 = h[/tex]
[tex]h = 162[/tex]
[tex]h = 162.0\ cm[/tex]
Hence, the patient's height is 162.0cm
