Answer:
x y
-2 36
-1 6
0 1
1 1/6
2 1/36
Step-by-step explanation:
Given
[tex]f(x) = (\frac{1}{6})^x[/tex]
Required
Complete the table
When x = -2.
Substitute -2 for
[tex]f(-2) = (\frac{1}{6})^{-2[/tex]
[tex]f(-2) = 1/\frac{1}{36}[/tex]
[tex]f(-2) = 36[/tex]
When x = -1
[tex]f(-1) = (\frac{1}{6})^{-1[/tex]
[tex]f(-1) = 1/\frac{1}{6}[/tex]
[tex]f(-1) = 6[/tex]
When x = 0
[tex]f(0) = \frac{1}{6}^0[/tex]
[tex]f(0) = 1[/tex]
When x = 1
[tex]f(1) = \frac{1}{6}^1[/tex]
[tex]f(1) = \frac{1}{6}[/tex]
When x = 2
[tex]f(2) = \frac{1}{6}^2[/tex]
[tex]f(2) = \frac{1}{36}[/tex]
