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8) in the diagram below the distance of AC is X+32. Find the value of AB.

8 In The Diagram Below The Distance Of AC Is X32 Find The Value Of AB class=

Answer :

13+2x+12=x+32
25+2x=x+32
X=7
So AB would be 27

Answer:

AB = 27

Step-by-step explanation:

A, B and C lie on a straight line, then

AB + BC = AC , substitute values

13 + 2x + 12 = x + 32

2x + 25 = x + 32 ( subtract x from both sides )

x + 25 = 32 ( subtract 25 from both sides )

x = 7

Thus

AB = 13 + 2x = 13 + 2(7) = 13 + 14 = 27

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