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Physics

Answered

2. If a spring has a spring constant of 400 N/m, how much elastic potential
energy is stored when the spring is stretched by 0.25 m?

Answer :

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Answer:

The kinetic energy of a spring is equal to its elastic potential energy.

The elastic potential energy is 12.5N-m or 12.5 Joules.

Explanation:

[tex] = \frac{1}{2} k {x}^{2} \\ = \frac{1}{2} (400)( {.25)}^{2} \\ = 12.5[/tex]

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