307433GO
307433GO
Chemistry
Answered
How many molecules are in 643.21 grams of Mg3(PO4)2?
Answer :
GIZELLERAMIREZ05GO
GIZELLERAMIREZ05GO
Answer:
643.21g 1 mol 6.022^23
262.87 g 1 mol
= 1.4735E24 [Mg3(PO4)2]
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