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Kareem threw a basketball from the basketball court toward the hoop. The function that models the height, in
feet, of the ball after a seconds is h(t) = -16t^2 +12t +8 If the hoop is 10 feet high, how long is the
ball in the air before it goes through the hoop?

Answer :

MHANIFAGO

Answer:

  • 1/2 of a second

Step-by-step explanation:

Given function:

  • h(t) = -16t^2 +12t +8

Finding the value of t when h(t) = 10 feet:

  • 10 = -16t^2 +12t +8
  • -16t^2 +12t - 2 = 0
  • 8t^2 - 6t + 1 = 0
  • t = (6 ± √6²-8*4)/16 = (6 ± √4)/16 = (6 ± 2)/16
  • t = 1/2
  • t = 1/4

There are two solutions. 1/2 of a second would be the answer as the ball should go up and then down to go through the hoop.

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