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Determine the center and radius of the following circle equation: x^2+y^2-14x+4y+52=0 x 2 +y 2 −14x+4y+52=0

Answer :

CHOISUNGHYUNGO

Step-by-step explanation:

x² + y² - 14x + 4y + 52 = 0

(x - 7)² - 49 + (y + 2)² - 4 + 52 = 0

(x - 7)² + (y + 2)² = 1

Hence the circle's center is (7, -2) and the radius is 1.

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