Answer:
[tex]\frac{2}{k+2}[/tex]
Step-by-step explanation:
Given the expression:
[tex]\frac{4k+2}{k^2-4} * \frac{k-2}{2k+1}[/tex]
We are to find the product as shown:
[tex]= \frac{4k+2}{k^2-4} * \frac{k-2}{2k+1}\\\\= \frac{2(2k+1)}{k^2-2^2} * \frac{k-2}{2k+1}\\\\= \frac{2(2k+1)}{(k-2)(k+2)} * \frac{k-2}{2k+1}\\\\= \frac{2}{k+2} * 1\\\\= \frac{2}{k+2}[/tex]
Hence the required function is [tex]\frac{2}{k+2}[/tex]
