This question is incomplete, its missing an image which will be uploaded along this Answer.
Answer:
the normal component of force F_n is F((√(r²-s²)) / r)
the tangential component of force F_t is F(s/r)
Explanation:
Given the data in the image;
from the free body diagram, we write the expression for ∅
sin∅ = s/r
cos∅ = (√(r²-s²)) / r
now expression for normal component of force is;
F_n = Fcos∅
we substitute
F_n = F((√(r²-s²)) / r)
Therefore, the normal component of force F_n is F((√(r²-s²)) / r)
Also for force F_t
F_t = Fsin∅
we substitute
F_t = F(s/r)
Therefore, the tangential component of force F_t is F(s/r)
