Answer:
1.510 × 10⁻¹³ g
Explanation:
Step 1: Given data
Number of atoms of vanadium: 1.000 × 10⁹ atoms
Step 2: Calculate the molecules of V₂O₅ that contain 1.000 × 10⁹ atoms of V
Each molecule of V₂O₅ has 2 atoms of V.
1.000 × 10⁹ atom V × (1 molecule V₂O₅/2 atom V) = 0.5000 × 10⁹ molecule V₂O₅
Step 3: Calculate the moles corresponding to 0.5000 × 10⁹ molecules of V₂O₅
We will use Avogadro's number: there are 6.022 × 10²³ molecules of V₂O₅ in 1 mole of V₂O₅.
0.5000 × 10⁹ molecule × (1 mol/6.022 × 10²³ molecule) = 8.303 × 10⁻¹⁶ mol
Step 4: Calculate the mass corresponding to 8.303 × 10⁻¹⁶ moles of V₂O₅
The molar mass of V₂O₅ is 181.88 g/mol.
8.303 × 10⁻¹⁶ mol × 181.88 g/mol = 1.510 × 10⁻¹³ g
