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Isopropyl alcohol (c3h7OH) burns in air according to this equation:
2C3H7OH + 9O2 -> 6CO2 + 8H2O
a) calculate the moles of oxygen needed to react with 3.40 mol C3H7OH
b) find the moles of each product formed when 3.40 mol C3H7OH reacts with oxygen

Answer :

DSDRAJLINGO

Answer:

a) 15.3 mol O₂

b) 10.2 mol CO₂; 13.6 mol H₂O

Explanation:

Step 1: Write the balanced equation

2 C₃H₇OH + 9 O₂ ⇒ 6 CO₂ + 8 H₂O

Step 2: Calculate the moles of O₂ that react with 3.40 moles of C₃H₇OH

The molar ratio of C₃H₇OH to O₂ is 2:9. The moles of O₂ required are 9/2 × 3.40 mol = 15.3 mol

Step 3: Calculate the moles of CO₂ produced from 3.40 moles of C₃H₇OH

The molar ratio of C₃H₇OH to CO₂ is 2:6. The moles of CO₂ produced are 6/2 × 3.40 mol = 10.2 mol

Step 4: Calculate the moles of H₂O produced from 3.40 moles of C₃H₇OH

The molar ratio of C₃H₇OH to H₂O is 2:8. The moles of H₂O produced are 8/2 × 3.40 mol = 13.6 mol

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