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5. How much power is dissipated when 0.2 ampere of current flows through a 100-ohm resistor ?​

Answer :

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Answer:

4 W

Step-by-step explanation:

Electrical power, P = I²R where I = current and R = resistance.

Given that I = 0.2 A and R = 100 Ω,

P = I²R

P = (0.2 A)² × 100 Ω

P = 0.04 A² × 100 Ω

P = 4 W

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