Answer:
The volume of a right circular cone that has a height of 16 m and a base with a circumference of 14.7 m is 3,620.62 m³
Step-by-step explanation:
The right cone (or cone of revolution, or right circular cone) is the solid of revolution formed by rotating a right triangle around one of its legs. The bottom circle of the cone is called the base. That is, a cone is a three-dimensional figure with a circular base. A curved surface connects the base and the vertex.
The volume of a 3-dimensional solid is the amount of space it occupies.
The volume V of a cone with radius r is one-third the area of the base B times the height h. This is:
[tex]V=\frac{1}{3}*A*h[/tex]
where A=π*r²
Then: V=[tex]\frac{1}{3}[/tex] *π*r²*h
In this case r=14.7 m and h=16 m. Replacing:
V=[tex]\frac{1}{3}[/tex] *π*(14.7 m)²*16 m
Solving, you get:
V=3,620.62 m³
The volume of a right circular cone that has a height of 16 m and a base with a circumference of 14.7 m is 3,620.62 m³
