Answer :
The quotient of [tex]20\sqrt{z^{6} }[/tex] ÷ [tex]\sqrt{16z^{7} }[/tex] in simplest radical form is [tex]\frac{5\sqrt{z} }{z}[/tex].
How to express a simplest radical form?
Expressing in simplest radical form just means simplifying a radical so that there are no more square roots, cube roots, 4th roots, etc left to find. It also means removing any radicals in the denominator of a fraction.
Given
[tex]20\sqrt{z^{6} }[/tex] ÷ [tex]\sqrt{16z^{7} }[/tex]
Rewrite as fraction: [tex]\frac{20\sqrt{z^{6} } }{\sqrt{16z^{7} } }[/tex]
Factor and rewrite the radicand in exponential form: [tex]\frac{20\sqrt{z^{6} } }{\sqrt{4^{2}. z^{6} .z} }[/tex]
Rewrite the expression using [tex]\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}[/tex] :
= [tex]\frac{20\sqrt{z^{6} } }{\sqrt{4^{2} .\sqrt{z^{6}.\sqrt{z} } } }[/tex]
Simply the radical expression, we get:
= [tex]\frac{20z^{3} }{4z^{3}\sqrt{z} }[/tex]
Reduce fraction to the lowest term by canceling the greater common factor, we get
= [tex]\frac{5}{\sqrt{z} }[/tex]
Rationalize the denominator
= [tex]\frac{5\sqrt{z} }{\sqrt{z} .\sqrt{z} }[/tex]
= [tex]\frac{5\sqrt{z} }{z}[/tex]
Hence, the quotient of [tex]20\sqrt{z^{6} }[/tex] ÷ [tex]\sqrt{16z^{7} }[/tex] in simplest radical form is [tex]\frac{5\sqrt{z} }{z}[/tex].
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