Answer:
An equation of the line in a slope intercept form has a slope of -6 and passes through the point (2, -4) is: [tex]\mathbf{y=-6x+8}[/tex]
Step-by-step explanation:
We need to write an equation of the line in a slope intercept form has a slope of -6 and passes through the point (2, -4)
The equation in slope-intercept form is : [tex]y=mx+b[/tex] where m is slope and b is y-intercept.
We need to find slope and y-intercept for our equation.
In the question, we are given slope m = -6
Now, we need to find y-intercept.
Using slope m = -6 and the point (2,-4) we can find y-intercept
[tex]y=mx+b\\-4=-6(2)+b\\-4=-12+b\\b=12-4\\b=8[/tex]
So, we get y-intercept : b = 8
Now, the equation of line having slope m = -6 and y-intercept : b = 8 in slope-intercept form will be:
[tex]y=mx+b\\y=-6x+8[/tex]
An equation of the line in a slope intercept form has a slope of -6 and passes through the point (2, -4) is: [tex]\mathbf{y=-6x+8}[/tex]
