Answer:
a) [tex]\mathbf{ f(g(x))=x+2\sqrt{x} +1}[/tex]
b) [tex]\mathbf{f(g(9))=16}[/tex]
Step-by-step explanation:
We are given:
[tex]f(x)=(x-2)^2\\g(x)=\sqrt{x} +3[/tex]
We need to find [tex]a) f(g(x))\\b) f(g(9))[/tex]
a) First finding: [tex]f(g(x))[/tex]
It can be found by putting the value of g(x) into f(x)
We are given:
[tex]f(x)=(x-2)^2\\Put\:x=g(x)\:i.e. \: x= \sqrt{x} +3\\f(g(x))=(\sqrt{x} +3-2)^2\\Now\: solving:\\f(g(x))=(\sqrt{x} +1)^2\\Using\:formula\:\mathbf{(a+b)^2=a^2+2ab+b^2}\\f(g(x))=(\sqrt{x})^2+2(\sqrt{x} )(1)+(1)^2\\ f(g(x))=x+2\sqrt{x} +1[/tex]
SO, we get: [tex]\mathbf{ f(g(x))=x+2\sqrt{x} +1}[/tex]
b) Now finding: [tex]f(g(9))[/tex]
It can be found by putting x=9 in f(g(x))
We have:
[tex]f(g(x))=x+2\sqrt{x} +1\\Put\:x=9\\f(g(9))=9+2\sqrt{9}+1\\We\:know\: \sqrt{9}=3\\ f(g(9))=9+2(3)+1\\f(g(9))=9+6+1\\f(g(9))=16[/tex]
So, we get: [tex]\mathbf{f(g(9))=16}[/tex]
