Unit 11: Volume and Surface Area Homework 1: Area of Plane Figures- Find Area.

To find the area of a triangle, you take the base and multiply by the height, and then divide by 2. Hence giving me the answers I obtained in #4 and #10.

A square is equal on all sides, so you would just square the measurement of the one side.

To find the area of a circle, you would do pi times the radius^2. Since this is a semicircle, you actually should divide the number you got by 2. (Which is why I did so up above).

I hope this helps!

MRROYALGO MRROYALGO · Answer 2

The area of a shape is the amount of space it can occupy.

The areas of the shapes are: 216cm[tex]^2,[/tex], 309.76mm[tex]^2,[/tex],760.61in[tex]^2,[/tex] and 148.92 in[tex]^2,[/tex] respectively

(a) Triangle

Given that:

[tex]Base = 27cm[/tex]

[tex]Height = 16cm[/tex]

The area is:

[tex]Area = 0.5 \times Base \times Height[/tex]

[tex]Area = 0.5 \times 27cm \times 16cm[/tex]

[tex]Area = 216cm^2[/tex]

(b) Square

Given that:

[tex]Length = 17.6mm[/tex]

The area is:

[tex]Area = Length^2[/tex]

[tex]Area = (17.6mm)^2[/tex]

[tex]Area = 309.76mm^2[/tex]

(c) Semi-circle

Given that:

[tex]diameter =44in[/tex]

First, calculate the radius (r)

[tex]r = 0.5 \times diameter[/tex]

[tex]r = 0.5 \times 44in[/tex]

[tex]r = 22in[/tex]

The area is:

[tex]Area = \frac{\pi r^2}{2}[/tex]

[tex]Area = \frac{3.143 \times (22in)^2}{2}[/tex]

[tex]Area = 760.61in^2[/tex]

(d) Triangle

Given that:

[tex]Base = 20.4in[/tex]

[tex]Height = 14.6in[/tex]

The area is:

[tex]Area = 0.5 \times Base \times Height[/tex]

[tex]Area = 0.5 \times 20.4in \times 14.6in[/tex]

[tex]Area = 148.92in^2[/tex]

Hence, the areas are: 216cm[tex]^2,[/tex], 309.76mm[tex]^2,[/tex],760.61in[tex]^2,[/tex] and 148.92 in[tex]^2,[/tex] respectively