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What average net force is required to accelerate a 3950 kg bus to a speed of 25m/s in 10.5 s?

Answer :

Answer:

Explanation:

ACCELERATION = CHANGE IN VELOCITY

                                          TIME  TAKEN

∴ a = 25 - 0

         10.5

∴ a =   50    

           21    

by using f = ma,

we get , f =   3950 ×  50                                                                                  

                                     21

∴  A FORCE OF 9404.8 N IS NEEDED TO ACCELERATE A BUS OF 3950 KG.

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