Answer:
[tex]\huge\boxed{j=45}[/tex]
Step-by-step explanation:
[tex]-2j=-90\qquad|\text{divide both sides by (-2)}\\\\\dfrac{-2j}{-2}=\dfrac{-90}{-2}\qquad|\text{we know}\ \dfrac{(-)}{(-)}\to(+)\\\\\dfrac{2\!\!\!\!\diagup j}{2\!\!\!\!\diagup}=\dfrac{90}{2}\\\\j=45[/tex]
