Answer:
[tex]in (y\sqrt{\frac{x}{y}}) =\frac{1}{2} in(x)-\frac{1}{2} in(z) +in(y)[/tex]
Step-by-step explanation:
From the question we are told that the expression [tex]ln(y √x/z[/tex]
[tex]in (y\sqrt{\frac{x}{y}})[/tex]
[tex]in(y)+in(y\sqrt{\frac{x}{y}})[/tex]
[tex]in(xy)=in(x)+in(y)[/tex]
[tex]in(xy)=in\frac{x}{z} ^1^/^2 +in(y)[/tex]
[tex]in(xy)=\frac{1}{2} in(\frac{x}{z}) +in(y)[/tex]
[tex]in(xy)=\frac{1}{2} in(x)-in(z) +in(y)[/tex]
[tex]in(xy)=\frac{1}{2} in(x)-\frac{1}{2} in(z) +in(y)[/tex]
Mathematically
[tex]in (y\sqrt{\frac{x}{y}}) =\frac{1}{2} in(x)-\frac{1}{2} in(z) +in(y)[/tex]
