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A horizontal net force is exerted on a 2.0 kg object at rest. The object starts at x=0 m and travels 8.0 m along a horizontal frictionless surface.
What is the velocity of the object
Round answer to 2 significant digits
____ m/s

A Horizontal Net Force Is Exerted On A 20 Kg Object At Rest The Object Starts At X0 M And Travels 80 M Along A Horizontal Frictionless Surface What Is The Veloc class=

Answer :

LAMMETTHASHGO

There's a constant force of 35 N exerted on the object of mass 2.0 kg, so it undergoes an acceleration a of

35 N = (2.0 kg) a   →   a = 17.5 m/s²

The object travels 8.0 m, so that it attains a velocity v of

v ² = 2 (17.5 m/s²) (8.0 m)   →   v ≈ 16.73 m/s ≈ 17 m/s

EDUARD22SLYGO

The velocity of the 2 Kg object which travels 8 m along the horizontal frictionless surface is 17 m/s

How to determine the acceleration

  • Force (F) = 35 N
  • Mass (m) = 2 Kg
  • Acceleration (a) =?

a = F / m

a = 35 / 2

a = 17.5 m/s²

How to determine the velocity

  • Initial velocity (u) = 0 m/s
  • Distance (s) = 8 m
  • Acceleration (a) = 17.5 m/s²
  • Final velocity (v) =?

v² = u² + 2as

v² = 0² + (2 × 17.5 × 8)

v² = 280

Take the square root of both side

v = √280

v = 17 m/s

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