Answer:
The value of each missing number is 9.
Step-by-step explanation:
Given that:
Average of 6 numbers = 12
The numbers 18,16 and 11 are given.
As the other three numbers are of same value.
Let,
x be the missing number.
Sum of all numbers = 18+16+11+x+x+x
Sum of all numbers = 45+3x
Average = [tex]\frac{Sum\ of\ quantities}{Number\ of\ quantites}[/tex]
[tex]12=\frac{45+3x}{6}\\12*6 = 45+3x\\72=45+3x\\72-45=3x\\27=3x\\\frac{3x}{3}=\frac{27}{3}\\x=9[/tex]
Hence,
The value of each missing number is 9.
