Answer :
Answer: 23 g
the mol of Fe is 11,5/56 = 23/112 (mol)
the mol of CO is [tex]\frac{2,63.10^{24} }{6.10^{23} }= \frac{263}{60}[/tex] (mol)
we have:
Fe2O3 + 3CO => 2Fe + 3CO2
23/112 69/112 23/56
=> the mol of Fe is 23/56 mol
=> the mass of Fe is 23/56.56 = 23 (g)
Explanation: