Answer:
(-2,10)=x1,y1
(1,1)=x2,y2
we have,
(y-y1)=(y2-y1)/(x2,x1)[(x-x1)]
(y-10)=(1-10)/(1+2)[x+2]
y-10=-9/3(x+2)
y-10=-3(x+2)
y-10=3x+6
y=3x+16
Answer:
Step-by-step explanation:
The slope of a line passing through two points: (x₂, y₂) and (x₁, y₁) is:
[tex]\bold{m=\dfrac{y_2-y_1}{x_2-x_1}}[/tex]
(-2, 10) ⇒ x₁ = -2, y₁ = 10
(1, 1) ⇒ x₂ = 1, y₂ = 1
So:
[tex]\bold{m=\dfrac{1-10}{1+2}=\dfrac{-9}{3}=-3}[/tex]
The point-slope form of equation of line is y - y₀ = m(x - x₀)
We can pick any of given poins, so:
x₀ = 1, y₀ = 1 and m = -3
y - 1 = -3(x - 1)
y = -3x + 3 + 1
y = -3x + 4 ← slope intercept form of the line
