The new coordinate of vertex B if the triangle is dilated with a center at the origin by a scale factor of 1/3 is (1,2) and this can be determined by using the given data.
Given :
After the dilation of 1/3 the coordinate of the triangle becomes:
[tex]\rm A(-2,2) \to A'(-2\times \dfrac{1}{3},2\times \dfrac{1}{3}) = A'\left(\dfrac{-2}{3},\dfrac{2}{3}\right)[/tex]
[tex]\rm B(3,6) \to B'(3\times \dfrac{1}{3},6\times \dfrac{1}{3}) = B'\left(1,2)[/tex]
[tex]\rm C(1,-2) \to C'(1\times \dfrac{1}{3},-2\times \dfrac{1}{3}) = C'\left(\dfrac{1}{3},\dfrac{-2}{3}\right)[/tex]
The new coordinate of vertex B if the triangle is dilated with a center at the origin by a scale factor of 1/3 is (1,2).
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