Hey there!
Molar mass NaCl = 58.44 g/mol
58.44 g ----------------- 22.4 ( at STP )
3.2 g -------------------- Volume ??
Volume = ( 3.2 x 22.4 ) / 58.44
Volume = 71.68 / 58.44
Volume = 1.226 L
Hope this helps!
Answer:
V = 0.56 L
Explanation:
Given data:
Mass of NaCl = 3.2 g
Volume of chlorine gas = ?
Pressure and temperature = standard
Solution:
Chemical equation:
2NaCl → 2Na + Cl₂
Number of moles of NaCl:
Number of moles = mass/molar mass
Number of moles = 3.2 g/ 58.44 g/mol
Number of moles = 0.05 mol
Now we will compare the moles of NaCl with chlorine;
NaCl : Cl₂
2 : 1
0.05 : 1/2×0.05 = 0.025 mol
Volume of chlorine:
PV = nRT
V = nRT/P
V = 0.025 mol × 0.0821 atm.L/mol.K × 273 K / 1 atm
V = 0.56 L
