Answer:
[tex]x = 2[/tex]
Step-by-step explanation:
Given
Conjecture: [tex]x + 3 < x^2[/tex] --- (Missing)
Required
Which value of x prove the conjecture otherwise
To do this , we simply substitute the values of x in the options
[tex]1.\ x = -\frac{1}{3}[/tex]
This is negative;
So, there is no need to check
[tex]2.\ x = -3[/tex]
This is also negative;
So, there is no need to check
[tex]3.\ x = 2[/tex]
[tex]x + 3 < x^2[/tex]
[tex]2 + 3 < 2^2[/tex]
[tex]5 < 4[/tex]
This value of x is false because 5 is not less than 4
[tex]4.\ x = 3[/tex]
[tex]x + 3 < x^2[/tex]
[tex]3 + 3 < 3^2[/tex]
[tex]6 < 9[/tex]
