Answer:
Solving the expression [tex]\frac{3}{4}n=-1\frac{3}{4}n-18[/tex] we get [tex]\mathbf{n=-\frac{36}{5} }[/tex]
Step-by-step explanation:
We need to solve the expression: [tex]\frac{3}{4}n=-1\frac{3}{4}n-18[/tex]
Solving:
[tex]\frac{3}{4}n=-1\frac{3}{4}n-18[/tex]
First we convert mixed fraction into improper fraction
[tex]\frac{3}{4}n=-\frac{7}{4}n-18[/tex]
Now adding 7/4 n on both sides
[tex]\frac{3}{4}n+\frac{7}{4}n=-\frac{7}{4}n-18+\frac{7}{4}n\\\frac{3}{4}n+\frac{7}{4}n=-18[/tex]
Now, taking LCM on left side
LCM of 4 and 4 is 4
[tex]\frac{3}{4}n+\frac{7}{4}n=-18\\\frac{3*1n+7*1n}{4}=-18\\\frac{3n+7n}{4}=-18\\\frac{10n}{4}=-18[/tex]
Now, multiply both sides by 4/10
[tex]\frac{10n}{4}\times \frac{4}{10} =-18\times \frac{4}{10}\\n=-\frac{36}{5}[/tex]
So, solving the expression [tex]\frac{3}{4}n=-1\frac{3}{4}n-18[/tex] we get [tex]\mathbf{n=-\frac{36}{5} }[/tex]
