Answer:
The solution for given system of equation is: [tex]x=\frac{1}{5}\:and\:y=\frac{-9}{5}[/tex] and ordered pair is: [tex]\mathbf{(\frac{1}{5},\frac{-9}{5})}[/tex]
So, (1,3) is not solution to the given system of equations.
Step-by-step explanation:
we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.
The system of equation given is:
[tex]y=6x-3\\y=x-2[/tex]
Solving:
Let:
[tex]y=6x-3--eq(1)\\y=x-2--eq(2)[/tex]
Put value of y from equation 2 into equation 1
[tex]y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}[/tex]
Now, put value of x in equation 2 to find value of y
[tex]y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}[/tex]
So, the solution for given system of equation is: [tex]x=\frac{1}{5}\:and\:y=\frac{-9}{5}[/tex] and ordered pair is: [tex]\mathbf{(\frac{1}{5},\frac{-9}{5})}[/tex]
So, (1,3) is not solution to the given system of equations.
