[tex]\frac{n+1}{2} =-\frac{3}{4}[/tex]

Answer :

Answer:

[tex]:\implies\tt \dfrac{n + 1}{2} = -\dfrac{3}{4} \\ \\ \\ [/tex]

Cross multiplying both the sides we get :

[tex]:\implies\tt (n + 1) \times 4= -3 \times 2 \\ \\ \\ [/tex]

[tex]:\implies\tt 4n + 4= -6 \\ \\ \\ [/tex]

[tex]:\implies\tt 4n = -6 - 4 \\ \\ \\ [/tex]

[tex]:\implies\tt 4n = -10 \\ \\ \\ [/tex]

[tex]:\implies\tt n = \dfrac{-10}{4}\\ \\ \\ [/tex]

[tex]:\implies\tt n = \dfrac{-5}{2}\\ \\ \\ [/tex]

[tex]:\implies \ddag \: \gray{ \underline{ \boxed{\tt n = - 2.5}}} \: \ddag\\ \\ \\ [/tex]