REEDH25GO REEDH25GO Chemistry Answered could someone help me with this please? Objective: Determine the thickness of Aluminum foil in both cm and atom units. Given Information: Density of Aluminum = 2.70 g/cm3 Diameter of Aluminum Atom = .0000000286 cm Volume of Sample = Mass of Sample / Density of Sample Volume of Sample = L x W x H* (*H = thickness of sample) Data and Results Include any data collected, calculations, and results below. (Pictures of your work are fine.) Conclusion Aluminum foil is _________ cm thick. Aluminum foil is _________ atoms thick.