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Parallelogram ABCD has vertices at A (0, 0), B (3, 6), C (5, 5), and D (2, -1).
Which conclusion can be made?
O ABL BC; therefore, ABCD is a square.
O ABL BC; therefore, ABCD is a rectangle.
O AB = BC; therefore, ABCD is a square.
O AB = BC; therefore, ABCD is a rhombus.

Parallelogram ABCD Has Vertices At A 0 0 B 3 6 C 5 5 And D 2 1 Which Conclusion Can Be Made O ABL BC Therefore ABCD Is A Square O ABL BC Therefore ABCD Is A Rec class=

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