Select the correct answer form each drop-down menu.
Given: m/AOB = 42"
m/EOF=66
Prove m/COD = 72°
Complete the proof
It is given that mZAOB 42 and m/BOP 66 By the
m/BOC
m/AOC+m/COD 180° After application of the
m/AOC-108", and by the
ZEOF BOC Then
COD=7Z
LOOO