in Programming in C, if
int p[2] [3] [4] = {
{{7, 4}, {0, -3}, {23, 12}},
{{13, 4}, {5, 9}, {3, 1}}};
Address of P= 10245 and assume that the address is increment by 2 bytes.
Find the output for the following:
printf ("%d\n",p);
printf ("%d\n",**p);
printf ("%d\n",*(*(*(p+1)+2)));
printf ("%d\n",*(*(p+2)));
printf ("%d\n",*(*(p+1)+1));
printf("%d",sizeof(int));